3.1176 \(\int \frac{\cos ^4(c+d x) \sin ^3(c+d x)}{(a+b \sin (c+d x))^{3/2}} \, dx\)

Optimal. Leaf size=466 \[ -\frac{2 \left (a^2-b^2\right ) \sin ^4(c+d x) \cos (c+d x)}{a b^2 d \sqrt{a+b \sin (c+d x)}}+\frac{2 \left (40 a^2-33 b^2\right ) \sin ^3(c+d x) \cos (c+d x) \sqrt{a+b \sin (c+d x)}}{33 a b^3 d}-\frac{20 \left (32 a^2-27 b^2\right ) \sin ^2(c+d x) \cos (c+d x) \sqrt{a+b \sin (c+d x)}}{231 b^4 d}+\frac{8 a \left (480 a^2-419 b^2\right ) \sin (c+d x) \cos (c+d x) \sqrt{a+b \sin (c+d x)}}{1155 b^5 d}-\frac{8 \left (-592 a^2 b^2+640 a^4+15 b^4\right ) \cos (c+d x) \sqrt{a+b \sin (c+d x)}}{1155 b^6 d}+\frac{8 \left (-1664 a^4 b^2+369 a^2 b^4+1280 a^6+15 b^6\right ) \sqrt{\frac{a+b \sin (c+d x)}{a+b}} F\left (\frac{1}{2} \left (c+d x-\frac{\pi }{2}\right )|\frac{2 b}{a+b}\right )}{1155 b^7 d \sqrt{a+b \sin (c+d x)}}-\frac{8 a \left (-1344 a^2 b^2+1280 a^4+123 b^4\right ) \sqrt{a+b \sin (c+d x)} E\left (\frac{1}{2} \left (c+d x-\frac{\pi }{2}\right )|\frac{2 b}{a+b}\right )}{1155 b^7 d \sqrt{\frac{a+b \sin (c+d x)}{a+b}}}-\frac{2 \sin ^4(c+d x) \cos (c+d x) \sqrt{a+b \sin (c+d x)}}{11 b^2 d} \]

[Out]

(-2*(a^2 - b^2)*Cos[c + d*x]*Sin[c + d*x]^4)/(a*b^2*d*Sqrt[a + b*Sin[c + d*x]]) - (8*(640*a^4 - 592*a^2*b^2 +
15*b^4)*Cos[c + d*x]*Sqrt[a + b*Sin[c + d*x]])/(1155*b^6*d) + (8*a*(480*a^2 - 419*b^2)*Cos[c + d*x]*Sin[c + d*
x]*Sqrt[a + b*Sin[c + d*x]])/(1155*b^5*d) - (20*(32*a^2 - 27*b^2)*Cos[c + d*x]*Sin[c + d*x]^2*Sqrt[a + b*Sin[c
+ d*x]])/(231*b^4*d) + (2*(40*a^2 - 33*b^2)*Cos[c + d*x]*Sin[c + d*x]^3*Sqrt[a + b*Sin[c + d*x]])/(33*a*b^3*d
) - (2*Cos[c + d*x]*Sin[c + d*x]^4*Sqrt[a + b*Sin[c + d*x]])/(11*b^2*d) - (8*a*(1280*a^4 - 1344*a^2*b^2 + 123*
b^4)*EllipticE[(c - Pi/2 + d*x)/2, (2*b)/(a + b)]*Sqrt[a + b*Sin[c + d*x]])/(1155*b^7*d*Sqrt[(a + b*Sin[c + d*
x])/(a + b)]) + (8*(1280*a^6 - 1664*a^4*b^2 + 369*a^2*b^4 + 15*b^6)*EllipticF[(c - Pi/2 + d*x)/2, (2*b)/(a + b
)]*Sqrt[(a + b*Sin[c + d*x])/(a + b)])/(1155*b^7*d*Sqrt[a + b*Sin[c + d*x]])

________________________________________________________________________________________

Rubi [A]  time = 1.21402, antiderivative size = 466, normalized size of antiderivative = 1., number of steps used = 10, number of rules used = 8, integrand size = 31, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.258, Rules used = {2892, 3049, 3023, 2752, 2663, 2661, 2655, 2653} \[ -\frac{2 \left (a^2-b^2\right ) \sin ^4(c+d x) \cos (c+d x)}{a b^2 d \sqrt{a+b \sin (c+d x)}}+\frac{2 \left (40 a^2-33 b^2\right ) \sin ^3(c+d x) \cos (c+d x) \sqrt{a+b \sin (c+d x)}}{33 a b^3 d}-\frac{20 \left (32 a^2-27 b^2\right ) \sin ^2(c+d x) \cos (c+d x) \sqrt{a+b \sin (c+d x)}}{231 b^4 d}+\frac{8 a \left (480 a^2-419 b^2\right ) \sin (c+d x) \cos (c+d x) \sqrt{a+b \sin (c+d x)}}{1155 b^5 d}-\frac{8 \left (-592 a^2 b^2+640 a^4+15 b^4\right ) \cos (c+d x) \sqrt{a+b \sin (c+d x)}}{1155 b^6 d}+\frac{8 \left (-1664 a^4 b^2+369 a^2 b^4+1280 a^6+15 b^6\right ) \sqrt{\frac{a+b \sin (c+d x)}{a+b}} F\left (\frac{1}{2} \left (c+d x-\frac{\pi }{2}\right )|\frac{2 b}{a+b}\right )}{1155 b^7 d \sqrt{a+b \sin (c+d x)}}-\frac{8 a \left (-1344 a^2 b^2+1280 a^4+123 b^4\right ) \sqrt{a+b \sin (c+d x)} E\left (\frac{1}{2} \left (c+d x-\frac{\pi }{2}\right )|\frac{2 b}{a+b}\right )}{1155 b^7 d \sqrt{\frac{a+b \sin (c+d x)}{a+b}}}-\frac{2 \sin ^4(c+d x) \cos (c+d x) \sqrt{a+b \sin (c+d x)}}{11 b^2 d} \]

Antiderivative was successfully verified.

[In]

Int[(Cos[c + d*x]^4*Sin[c + d*x]^3)/(a + b*Sin[c + d*x])^(3/2),x]

[Out]

(-2*(a^2 - b^2)*Cos[c + d*x]*Sin[c + d*x]^4)/(a*b^2*d*Sqrt[a + b*Sin[c + d*x]]) - (8*(640*a^4 - 592*a^2*b^2 +
15*b^4)*Cos[c + d*x]*Sqrt[a + b*Sin[c + d*x]])/(1155*b^6*d) + (8*a*(480*a^2 - 419*b^2)*Cos[c + d*x]*Sin[c + d*
x]*Sqrt[a + b*Sin[c + d*x]])/(1155*b^5*d) - (20*(32*a^2 - 27*b^2)*Cos[c + d*x]*Sin[c + d*x]^2*Sqrt[a + b*Sin[c
+ d*x]])/(231*b^4*d) + (2*(40*a^2 - 33*b^2)*Cos[c + d*x]*Sin[c + d*x]^3*Sqrt[a + b*Sin[c + d*x]])/(33*a*b^3*d
) - (2*Cos[c + d*x]*Sin[c + d*x]^4*Sqrt[a + b*Sin[c + d*x]])/(11*b^2*d) - (8*a*(1280*a^4 - 1344*a^2*b^2 + 123*
b^4)*EllipticE[(c - Pi/2 + d*x)/2, (2*b)/(a + b)]*Sqrt[a + b*Sin[c + d*x]])/(1155*b^7*d*Sqrt[(a + b*Sin[c + d*
x])/(a + b)]) + (8*(1280*a^6 - 1664*a^4*b^2 + 369*a^2*b^4 + 15*b^6)*EllipticF[(c - Pi/2 + d*x)/2, (2*b)/(a + b
)]*Sqrt[(a + b*Sin[c + d*x])/(a + b)])/(1155*b^7*d*Sqrt[a + b*Sin[c + d*x]])

Rule 2892

Int[cos[(e_.) + (f_.)*(x_)]^4*((d_.)*sin[(e_.) + (f_.)*(x_)])^(n_)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)
, x_Symbol] :> Simp[((a^2 - b^2)*Cos[e + f*x]*(a + b*Sin[e + f*x])^(m + 1)*(d*Sin[e + f*x])^(n + 1))/(a*b^2*d*
f*(m + 1)), x] + (-Dist[1/(a*b^2*(m + 1)*(m + n + 4)), Int[(a + b*Sin[e + f*x])^(m + 1)*(d*Sin[e + f*x])^n*Sim
p[a^2*(n + 1)*(n + 3) - b^2*(m + n + 2)*(m + n + 4) + a*b*(m + 1)*Sin[e + f*x] - (a^2*(n + 2)*(n + 3) - b^2*(m
+ n + 3)*(m + n + 4))*Sin[e + f*x]^2, x], x], x] - Simp[(Cos[e + f*x]*(a + b*Sin[e + f*x])^(m + 2)*(d*Sin[e +
f*x])^(n + 1))/(b^2*d*f*(m + n + 4)), x]) /; FreeQ[{a, b, d, e, f, n}, x] && NeQ[a^2 - b^2, 0] && IntegersQ[2
*m, 2*n] && LtQ[m, -1] &&  !LtQ[n, -1] && NeQ[m + n + 4, 0]

Rule 3049

Int[((a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_.)*((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)])^(n_.)*((A_.) + (B_.)
*sin[(e_.) + (f_.)*(x_)] + (C_.)*sin[(e_.) + (f_.)*(x_)]^2), x_Symbol] :> -Simp[(C*Cos[e + f*x]*(a + b*Sin[e +
f*x])^m*(c + d*Sin[e + f*x])^(n + 1))/(d*f*(m + n + 2)), x] + Dist[1/(d*(m + n + 2)), Int[(a + b*Sin[e + f*x]
)^(m - 1)*(c + d*Sin[e + f*x])^n*Simp[a*A*d*(m + n + 2) + C*(b*c*m + a*d*(n + 1)) + (d*(A*b + a*B)*(m + n + 2)
- C*(a*c - b*d*(m + n + 1)))*Sin[e + f*x] + (C*(a*d*m - b*c*(m + 1)) + b*B*d*(m + n + 2))*Sin[e + f*x]^2, x],
x], x] /; FreeQ[{a, b, c, d, e, f, A, B, C, n}, x] && NeQ[b*c - a*d, 0] && NeQ[a^2 - b^2, 0] && NeQ[c^2 - d^2
, 0] && GtQ[m, 0] &&  !(IGtQ[n, 0] && ( !IntegerQ[m] || (EqQ[a, 0] && NeQ[c, 0])))

Rule 3023

Int[((a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_.)*((A_.) + (B_.)*sin[(e_.) + (f_.)*(x_)] + (C_.)*sin[(e_.) + (
f_.)*(x_)]^2), x_Symbol] :> -Simp[(C*Cos[e + f*x]*(a + b*Sin[e + f*x])^(m + 1))/(b*f*(m + 2)), x] + Dist[1/(b*
(m + 2)), Int[(a + b*Sin[e + f*x])^m*Simp[A*b*(m + 2) + b*C*(m + 1) + (b*B*(m + 2) - a*C)*Sin[e + f*x], x], x]
, x] /; FreeQ[{a, b, e, f, A, B, C, m}, x] &&  !LtQ[m, -1]

Rule 2752

Int[((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)])/Sqrt[(a_) + (b_.)*sin[(e_.) + (f_.)*(x_)]], x_Symbol] :> Dist[(b*c
- a*d)/b, Int[1/Sqrt[a + b*Sin[e + f*x]], x], x] + Dist[d/b, Int[Sqrt[a + b*Sin[e + f*x]], x], x] /; FreeQ[{a
, b, c, d, e, f}, x] && NeQ[b*c - a*d, 0] && NeQ[a^2 - b^2, 0]

Rule 2663

Int[1/Sqrt[(a_) + (b_.)*sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Dist[Sqrt[(a + b*Sin[c + d*x])/(a + b)]/Sqrt[a
+ b*Sin[c + d*x]], Int[1/Sqrt[a/(a + b) + (b*Sin[c + d*x])/(a + b)], x], x] /; FreeQ[{a, b, c, d}, x] && NeQ[a
^2 - b^2, 0] &&  !GtQ[a + b, 0]

Rule 2661

Int[1/Sqrt[(a_) + (b_.)*sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[(2*EllipticF[(1*(c - Pi/2 + d*x))/2, (2*b)
/(a + b)])/(d*Sqrt[a + b]), x] /; FreeQ[{a, b, c, d}, x] && NeQ[a^2 - b^2, 0] && GtQ[a + b, 0]

Rule 2655

Int[Sqrt[(a_) + (b_.)*sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Dist[Sqrt[a + b*Sin[c + d*x]]/Sqrt[(a + b*Sin[c +
d*x])/(a + b)], Int[Sqrt[a/(a + b) + (b*Sin[c + d*x])/(a + b)], x], x] /; FreeQ[{a, b, c, d}, x] && NeQ[a^2 -
b^2, 0] &&  !GtQ[a + b, 0]

Rule 2653

Int[Sqrt[(a_) + (b_.)*sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[(2*Sqrt[a + b]*EllipticE[(1*(c - Pi/2 + d*x)
)/2, (2*b)/(a + b)])/d, x] /; FreeQ[{a, b, c, d}, x] && NeQ[a^2 - b^2, 0] && GtQ[a + b, 0]

Rubi steps

\begin{align*} \int \frac{\cos ^4(c+d x) \sin ^3(c+d x)}{(a+b \sin (c+d x))^{3/2}} \, dx &=-\frac{2 \left (a^2-b^2\right ) \cos (c+d x) \sin ^4(c+d x)}{a b^2 d \sqrt{a+b \sin (c+d x)}}-\frac{2 \cos (c+d x) \sin ^4(c+d x) \sqrt{a+b \sin (c+d x)}}{11 b^2 d}+\frac{4 \int \frac{\sin ^3(c+d x) \left (\frac{1}{4} \left (96 a^2-77 b^2\right )-\frac{1}{2} a b \sin (c+d x)-\frac{3}{4} \left (40 a^2-33 b^2\right ) \sin ^2(c+d x)\right )}{\sqrt{a+b \sin (c+d x)}} \, dx}{11 a b^2}\\ &=-\frac{2 \left (a^2-b^2\right ) \cos (c+d x) \sin ^4(c+d x)}{a b^2 d \sqrt{a+b \sin (c+d x)}}+\frac{2 \left (40 a^2-33 b^2\right ) \cos (c+d x) \sin ^3(c+d x) \sqrt{a+b \sin (c+d x)}}{33 a b^3 d}-\frac{2 \cos (c+d x) \sin ^4(c+d x) \sqrt{a+b \sin (c+d x)}}{11 b^2 d}+\frac{8 \int \frac{\sin ^2(c+d x) \left (-\frac{9}{4} a \left (40 a^2-33 b^2\right )+3 a^2 b \sin (c+d x)+\frac{15}{4} a \left (32 a^2-27 b^2\right ) \sin ^2(c+d x)\right )}{\sqrt{a+b \sin (c+d x)}} \, dx}{99 a b^3}\\ &=-\frac{2 \left (a^2-b^2\right ) \cos (c+d x) \sin ^4(c+d x)}{a b^2 d \sqrt{a+b \sin (c+d x)}}-\frac{20 \left (32 a^2-27 b^2\right ) \cos (c+d x) \sin ^2(c+d x) \sqrt{a+b \sin (c+d x)}}{231 b^4 d}+\frac{2 \left (40 a^2-33 b^2\right ) \cos (c+d x) \sin ^3(c+d x) \sqrt{a+b \sin (c+d x)}}{33 a b^3 d}-\frac{2 \cos (c+d x) \sin ^4(c+d x) \sqrt{a+b \sin (c+d x)}}{11 b^2 d}+\frac{16 \int \frac{\sin (c+d x) \left (\frac{15}{2} a^2 \left (32 a^2-27 b^2\right )-\frac{3}{4} a b \left (20 a^2-9 b^2\right ) \sin (c+d x)-\frac{3}{4} a^2 \left (480 a^2-419 b^2\right ) \sin ^2(c+d x)\right )}{\sqrt{a+b \sin (c+d x)}} \, dx}{693 a b^4}\\ &=-\frac{2 \left (a^2-b^2\right ) \cos (c+d x) \sin ^4(c+d x)}{a b^2 d \sqrt{a+b \sin (c+d x)}}+\frac{8 a \left (480 a^2-419 b^2\right ) \cos (c+d x) \sin (c+d x) \sqrt{a+b \sin (c+d x)}}{1155 b^5 d}-\frac{20 \left (32 a^2-27 b^2\right ) \cos (c+d x) \sin ^2(c+d x) \sqrt{a+b \sin (c+d x)}}{231 b^4 d}+\frac{2 \left (40 a^2-33 b^2\right ) \cos (c+d x) \sin ^3(c+d x) \sqrt{a+b \sin (c+d x)}}{33 a b^3 d}-\frac{2 \cos (c+d x) \sin ^4(c+d x) \sqrt{a+b \sin (c+d x)}}{11 b^2 d}+\frac{32 \int \frac{-\frac{3}{4} a^3 \left (480 a^2-419 b^2\right )+\frac{3}{8} a^2 b \left (160 a^2-93 b^2\right ) \sin (c+d x)+\frac{9}{8} a \left (640 a^4-592 a^2 b^2+15 b^4\right ) \sin ^2(c+d x)}{\sqrt{a+b \sin (c+d x)}} \, dx}{3465 a b^5}\\ &=-\frac{2 \left (a^2-b^2\right ) \cos (c+d x) \sin ^4(c+d x)}{a b^2 d \sqrt{a+b \sin (c+d x)}}-\frac{8 \left (640 a^4-592 a^2 b^2+15 b^4\right ) \cos (c+d x) \sqrt{a+b \sin (c+d x)}}{1155 b^6 d}+\frac{8 a \left (480 a^2-419 b^2\right ) \cos (c+d x) \sin (c+d x) \sqrt{a+b \sin (c+d x)}}{1155 b^5 d}-\frac{20 \left (32 a^2-27 b^2\right ) \cos (c+d x) \sin ^2(c+d x) \sqrt{a+b \sin (c+d x)}}{231 b^4 d}+\frac{2 \left (40 a^2-33 b^2\right ) \cos (c+d x) \sin ^3(c+d x) \sqrt{a+b \sin (c+d x)}}{33 a b^3 d}-\frac{2 \cos (c+d x) \sin ^4(c+d x) \sqrt{a+b \sin (c+d x)}}{11 b^2 d}+\frac{64 \int \frac{-\frac{9}{16} a b \left (320 a^4-246 a^2 b^2-15 b^4\right )-\frac{9}{16} a^2 \left (1280 a^4-1344 a^2 b^2+123 b^4\right ) \sin (c+d x)}{\sqrt{a+b \sin (c+d x)}} \, dx}{10395 a b^6}\\ &=-\frac{2 \left (a^2-b^2\right ) \cos (c+d x) \sin ^4(c+d x)}{a b^2 d \sqrt{a+b \sin (c+d x)}}-\frac{8 \left (640 a^4-592 a^2 b^2+15 b^4\right ) \cos (c+d x) \sqrt{a+b \sin (c+d x)}}{1155 b^6 d}+\frac{8 a \left (480 a^2-419 b^2\right ) \cos (c+d x) \sin (c+d x) \sqrt{a+b \sin (c+d x)}}{1155 b^5 d}-\frac{20 \left (32 a^2-27 b^2\right ) \cos (c+d x) \sin ^2(c+d x) \sqrt{a+b \sin (c+d x)}}{231 b^4 d}+\frac{2 \left (40 a^2-33 b^2\right ) \cos (c+d x) \sin ^3(c+d x) \sqrt{a+b \sin (c+d x)}}{33 a b^3 d}-\frac{2 \cos (c+d x) \sin ^4(c+d x) \sqrt{a+b \sin (c+d x)}}{11 b^2 d}-\frac{\left (4 a \left (1280 a^4-1344 a^2 b^2+123 b^4\right )\right ) \int \sqrt{a+b \sin (c+d x)} \, dx}{1155 b^7}+\frac{\left (4 \left (1280 a^6-1664 a^4 b^2+369 a^2 b^4+15 b^6\right )\right ) \int \frac{1}{\sqrt{a+b \sin (c+d x)}} \, dx}{1155 b^7}\\ &=-\frac{2 \left (a^2-b^2\right ) \cos (c+d x) \sin ^4(c+d x)}{a b^2 d \sqrt{a+b \sin (c+d x)}}-\frac{8 \left (640 a^4-592 a^2 b^2+15 b^4\right ) \cos (c+d x) \sqrt{a+b \sin (c+d x)}}{1155 b^6 d}+\frac{8 a \left (480 a^2-419 b^2\right ) \cos (c+d x) \sin (c+d x) \sqrt{a+b \sin (c+d x)}}{1155 b^5 d}-\frac{20 \left (32 a^2-27 b^2\right ) \cos (c+d x) \sin ^2(c+d x) \sqrt{a+b \sin (c+d x)}}{231 b^4 d}+\frac{2 \left (40 a^2-33 b^2\right ) \cos (c+d x) \sin ^3(c+d x) \sqrt{a+b \sin (c+d x)}}{33 a b^3 d}-\frac{2 \cos (c+d x) \sin ^4(c+d x) \sqrt{a+b \sin (c+d x)}}{11 b^2 d}-\frac{\left (4 a \left (1280 a^4-1344 a^2 b^2+123 b^4\right ) \sqrt{a+b \sin (c+d x)}\right ) \int \sqrt{\frac{a}{a+b}+\frac{b \sin (c+d x)}{a+b}} \, dx}{1155 b^7 \sqrt{\frac{a+b \sin (c+d x)}{a+b}}}+\frac{\left (4 \left (1280 a^6-1664 a^4 b^2+369 a^2 b^4+15 b^6\right ) \sqrt{\frac{a+b \sin (c+d x)}{a+b}}\right ) \int \frac{1}{\sqrt{\frac{a}{a+b}+\frac{b \sin (c+d x)}{a+b}}} \, dx}{1155 b^7 \sqrt{a+b \sin (c+d x)}}\\ &=-\frac{2 \left (a^2-b^2\right ) \cos (c+d x) \sin ^4(c+d x)}{a b^2 d \sqrt{a+b \sin (c+d x)}}-\frac{8 \left (640 a^4-592 a^2 b^2+15 b^4\right ) \cos (c+d x) \sqrt{a+b \sin (c+d x)}}{1155 b^6 d}+\frac{8 a \left (480 a^2-419 b^2\right ) \cos (c+d x) \sin (c+d x) \sqrt{a+b \sin (c+d x)}}{1155 b^5 d}-\frac{20 \left (32 a^2-27 b^2\right ) \cos (c+d x) \sin ^2(c+d x) \sqrt{a+b \sin (c+d x)}}{231 b^4 d}+\frac{2 \left (40 a^2-33 b^2\right ) \cos (c+d x) \sin ^3(c+d x) \sqrt{a+b \sin (c+d x)}}{33 a b^3 d}-\frac{2 \cos (c+d x) \sin ^4(c+d x) \sqrt{a+b \sin (c+d x)}}{11 b^2 d}-\frac{8 a \left (1280 a^4-1344 a^2 b^2+123 b^4\right ) E\left (\frac{1}{2} \left (c-\frac{\pi }{2}+d x\right )|\frac{2 b}{a+b}\right ) \sqrt{a+b \sin (c+d x)}}{1155 b^7 d \sqrt{\frac{a+b \sin (c+d x)}{a+b}}}+\frac{8 \left (1280 a^6-1664 a^4 b^2+369 a^2 b^4+15 b^6\right ) F\left (\frac{1}{2} \left (c-\frac{\pi }{2}+d x\right )|\frac{2 b}{a+b}\right ) \sqrt{\frac{a+b \sin (c+d x)}{a+b}}}{1155 b^7 d \sqrt{a+b \sin (c+d x)}}\\ \end{align*}

Mathematica [A]  time = 6.57906, size = 326, normalized size = 0.7 \[ \frac{b \cos (c+d x) \left (8672 a^2 b^3 \sin (c+d x)+800 a^2 b^3 \sin (3 (c+d x))-16 \left (160 a^3 b^2-93 a b^4\right ) \cos (2 (c+d x))+40448 a^3 b^2-10240 a^4 b \sin (c+d x)-40960 a^5+280 a b^4 \cos (4 (c+d x))-2728 a b^4+330 b^5 \sin (c+d x)-255 b^5 \sin (3 (c+d x))-105 b^5 \sin (5 (c+d x))\right )-64 \left (-1664 a^4 b^2+369 a^2 b^4+1280 a^6+15 b^6\right ) \sqrt{\frac{a+b \sin (c+d x)}{a+b}} F\left (\frac{1}{4} (-2 c-2 d x+\pi )|\frac{2 b}{a+b}\right )+64 a \left (-1344 a^3 b^2-1344 a^2 b^3+1280 a^4 b+1280 a^5+123 a b^4+123 b^5\right ) \sqrt{\frac{a+b \sin (c+d x)}{a+b}} E\left (\frac{1}{4} (-2 c-2 d x+\pi )|\frac{2 b}{a+b}\right )}{9240 b^7 d \sqrt{a+b \sin (c+d x)}} \]

Antiderivative was successfully verified.

[In]

Integrate[(Cos[c + d*x]^4*Sin[c + d*x]^3)/(a + b*Sin[c + d*x])^(3/2),x]

[Out]

(64*a*(1280*a^5 + 1280*a^4*b - 1344*a^3*b^2 - 1344*a^2*b^3 + 123*a*b^4 + 123*b^5)*EllipticE[(-2*c + Pi - 2*d*x
)/4, (2*b)/(a + b)]*Sqrt[(a + b*Sin[c + d*x])/(a + b)] - 64*(1280*a^6 - 1664*a^4*b^2 + 369*a^2*b^4 + 15*b^6)*E
llipticF[(-2*c + Pi - 2*d*x)/4, (2*b)/(a + b)]*Sqrt[(a + b*Sin[c + d*x])/(a + b)] + b*Cos[c + d*x]*(-40960*a^5
+ 40448*a^3*b^2 - 2728*a*b^4 - 16*(160*a^3*b^2 - 93*a*b^4)*Cos[2*(c + d*x)] + 280*a*b^4*Cos[4*(c + d*x)] - 10
240*a^4*b*Sin[c + d*x] + 8672*a^2*b^3*Sin[c + d*x] + 330*b^5*Sin[c + d*x] + 800*a^2*b^3*Sin[3*(c + d*x)] - 255
*b^5*Sin[3*(c + d*x)] - 105*b^5*Sin[5*(c + d*x)]))/(9240*b^7*d*Sqrt[a + b*Sin[c + d*x]])

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Maple [B]  time = 1.581, size = 1356, normalized size = 2.9 \begin{align*} \text{result too large to display} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(cos(d*x+c)^4*sin(d*x+c)^3/(a+b*sin(d*x+c))^(3/2),x)

[Out]

-2/1155*(492*((a+b*sin(d*x+c))/(a-b))^(1/2)*(-(sin(d*x+c)-1)*b/(a+b))^(1/2)*(-(1+sin(d*x+c))*b/(a-b))^(1/2)*El
lipticE(((a+b*sin(d*x+c))/(a-b))^(1/2),((a-b)/(a+b))^(1/2))*a*b^6+60*((a+b*sin(d*x+c))/(a-b))^(1/2)*(-(sin(d*x
+c)-1)*b/(a+b))^(1/2)*(-(1+sin(d*x+c))*b/(a-b))^(1/2)*EllipticF(((a+b*sin(d*x+c))/(a-b))^(1/2),((a-b)/(a+b))^(
1/2))*b^7-5120*((a+b*sin(d*x+c))/(a-b))^(1/2)*(-(sin(d*x+c)-1)*b/(a+b))^(1/2)*(-(1+sin(d*x+c))*b/(a-b))^(1/2)*
EllipticE(((a+b*sin(d*x+c))/(a-b))^(1/2),((a-b)/(a+b))^(1/2))*a^7+140*a*b^6*sin(d*x+c)^6-200*a^2*b^5*sin(d*x+c
)^5+320*a^3*b^4*sin(d*x+c)^4-466*a*b^6*sin(d*x+c)^4-640*a^4*b^3*sin(d*x+c)^3+892*a^2*b^5*sin(d*x+c)^3-2560*a^5
*b^2*sin(d*x+c)^2+2048*a^3*b^4*sin(d*x+c)^2+266*a*b^6*sin(d*x+c)^2+640*a^4*b^3*sin(d*x+c)-692*a^2*b^5*sin(d*x+
c)-2368*a^3*b^4+60*a*b^6+2560*a^5*b^2-5868*((a+b*sin(d*x+c))/(a-b))^(1/2)*(-(sin(d*x+c)-1)*b/(a+b))^(1/2)*(-(1
+sin(d*x+c))*b/(a-b))^(1/2)*EllipticE(((a+b*sin(d*x+c))/(a-b))^(1/2),((a-b)/(a+b))^(1/2))*a^3*b^4+5120*((a+b*s
in(d*x+c))/(a-b))^(1/2)*(-(sin(d*x+c)-1)*b/(a+b))^(1/2)*(-(1+sin(d*x+c))*b/(a-b))^(1/2)*EllipticF(((a+b*sin(d*
x+c))/(a-b))^(1/2),((a-b)/(a+b))^(1/2))*a^6*b-3840*((a+b*sin(d*x+c))/(a-b))^(1/2)*(-(sin(d*x+c)-1)*b/(a+b))^(1
/2)*(-(1+sin(d*x+c))*b/(a-b))^(1/2)*EllipticF(((a+b*sin(d*x+c))/(a-b))^(1/2),((a-b)/(a+b))^(1/2))*a^5*b^2-6656
*((a+b*sin(d*x+c))/(a-b))^(1/2)*(-(sin(d*x+c)-1)*b/(a+b))^(1/2)*(-(1+sin(d*x+c))*b/(a-b))^(1/2)*EllipticF(((a+
b*sin(d*x+c))/(a-b))^(1/2),((a-b)/(a+b))^(1/2))*a^4*b^3+4392*((a+b*sin(d*x+c))/(a-b))^(1/2)*(-(sin(d*x+c)-1)*b
/(a+b))^(1/2)*(-(1+sin(d*x+c))*b/(a-b))^(1/2)*EllipticF(((a+b*sin(d*x+c))/(a-b))^(1/2),((a-b)/(a+b))^(1/2))*a^
3*b^4+1476*((a+b*sin(d*x+c))/(a-b))^(1/2)*(-(sin(d*x+c)-1)*b/(a+b))^(1/2)*(-(1+sin(d*x+c))*b/(a-b))^(1/2)*Elli
pticF(((a+b*sin(d*x+c))/(a-b))^(1/2),((a-b)/(a+b))^(1/2))*a^2*b^5-552*((a+b*sin(d*x+c))/(a-b))^(1/2)*(-(sin(d*
x+c)-1)*b/(a+b))^(1/2)*(-(1+sin(d*x+c))*b/(a-b))^(1/2)*EllipticF(((a+b*sin(d*x+c))/(a-b))^(1/2),((a-b)/(a+b))^
(1/2))*a*b^6+10496*((a+b*sin(d*x+c))/(a-b))^(1/2)*(-(sin(d*x+c)-1)*b/(a+b))^(1/2)*(-(1+sin(d*x+c))*b/(a-b))^(1
/2)*EllipticE(((a+b*sin(d*x+c))/(a-b))^(1/2),((a-b)/(a+b))^(1/2))*a^5*b^2-105*b^7*sin(d*x+c)^7+300*b^7*sin(d*x
+c)^5-255*b^7*sin(d*x+c)^3+60*b^7*sin(d*x+c))/b^8/cos(d*x+c)/(a+b*sin(d*x+c))^(1/2)/d

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Maxima [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\cos \left (d x + c\right )^{4} \sin \left (d x + c\right )^{3}}{{\left (b \sin \left (d x + c\right ) + a\right )}^{\frac{3}{2}}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(d*x+c)^4*sin(d*x+c)^3/(a+b*sin(d*x+c))^(3/2),x, algorithm="maxima")

[Out]

integrate(cos(d*x + c)^4*sin(d*x + c)^3/(b*sin(d*x + c) + a)^(3/2), x)

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Fricas [F]  time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{{\left (\cos \left (d x + c\right )^{6} - \cos \left (d x + c\right )^{4}\right )} \sqrt{b \sin \left (d x + c\right ) + a} \sin \left (d x + c\right )}{b^{2} \cos \left (d x + c\right )^{2} - 2 \, a b \sin \left (d x + c\right ) - a^{2} - b^{2}}, x\right ) \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(d*x+c)^4*sin(d*x+c)^3/(a+b*sin(d*x+c))^(3/2),x, algorithm="fricas")

[Out]

integral((cos(d*x + c)^6 - cos(d*x + c)^4)*sqrt(b*sin(d*x + c) + a)*sin(d*x + c)/(b^2*cos(d*x + c)^2 - 2*a*b*s
in(d*x + c) - a^2 - b^2), x)

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Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(d*x+c)**4*sin(d*x+c)**3/(a+b*sin(d*x+c))**(3/2),x)

[Out]

Timed out

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Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\cos \left (d x + c\right )^{4} \sin \left (d x + c\right )^{3}}{{\left (b \sin \left (d x + c\right ) + a\right )}^{\frac{3}{2}}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(d*x+c)^4*sin(d*x+c)^3/(a+b*sin(d*x+c))^(3/2),x, algorithm="giac")

[Out]

integrate(cos(d*x + c)^4*sin(d*x + c)^3/(b*sin(d*x + c) + a)^(3/2), x)